ALKALINITY
Definition:
The acid neutralizing capacity is known as alkalinity. It is due to OH-, CO32-, HCO3-.
1.Aim:
To determine the type and amount of alkalinity of the water sample
2.Chemicals required:
NaOH, HCl , Sample water, Phenolphthalein, Methyl orange
3.Principle:
There are five types of alkalinity.
i) OH- only ii) CO32- only iii) HCO3-.only iv) OH- and CO32- v) CO32-and HCO3-.
The other combinations are not possible. Because,
OH- + HCO3-. à H2O + CO32-, it again form carbonate.
The possible reactions are
1. OH- + H+ à H2O
2. CO32- + H+ à HCO3- ( Half neutralization of carbonate)
3. HCO3- + H+ à H2O + CO2
Phenolphtalein can be used as indicator for 1 & 2. But not for 3.
Methyl orange is used for all 1 , 2 & 3 reactions.
4. Formula table:
S.No | Case | OH- | CO32--. | HCO3-. |
1 | P=0 | Nil | Nil | M |
2 | P=M | P=M | Nil | Nil |
3 | P = ½ M | Nil | 2P | Nil |
4 | P > ½ M | 2P – M | 2(M – P) | Nil |
5 | P < ½ M | Nil | 2P | (M – 2P) |
5. Short Procedure
S.No | Content | Titration-I Standardisation of HCl | Titration-II Alkalinity estimation |
1 | Burette | HCl acid | Standard HCl |
2 | Pipette(20 ml) | Standard NaOH | Water sample |
3 | Indicator | Phenolphtahlein | i)Phenolphthalein ii) Methyl orange |
4 | Endpoint | Disappearance of pink colour | i)Disappearance of pink colour ii) Appearance of pink colour |
6. Calculation:
Step-1 : Standardisation of HCl
Volume of NaOH (V1) = 20ml
Strength of NaOH (N1) =0.1N
Volume of HCl (V2) = x ml
Strength of HCl (N2) = ?
As per volumetric principle, V1N1 = V2N2
N2 = V1N1 / V2
Step -2 : Estimation of alkalinity:
(let us consider P=8 and M = 10, as P>1/2 M , this comes under case (iv). We are having OH- and CO32- alkalinity)
a)Amount of OH-
Volume of HCl (V1) = (2P – M ) ml
Strength of HCl (N1) = From step 1
Volume of water (V2) = 20 ml
Strength of OH- in water (N2)= ?
As per volumetric principle, V1N1 = V2N2
N2 = V1N1 / V2
Amount of OH- in water = N2 X 50 X 1000 ppm
( we are multiplying by 50 as it is eq.wt of CaCO3.
We are multiplying by 1000 to convert it for gram to milligram)
b)Amount of CO32-
Volume of HCl (V1) = 2(M-P ) ml
Strength of HCl (N1) = From step 1
Volume of water (V2) = 20 ml
Strength of CO32- in water (N2)= ?
As per volumetric principle, V1N1 = V2N2
N2 = V1N1 / V2
Amount of CO32-in water = N2 X 50 X 1000 ppm
( we are multiplying by 50 as it is eq.wt of CaCO3.
We are multiplying by 1000 to convert it for gram to milligram)
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